python quiz 5

 

  Start date :- 12/05/2021                                End date :- 25/05/2021

PYTHON QUIZ 5..

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Q.1. What does the following Python3 code do? (using python 3.X version): n = int (input('Enter a number?'))
i = 1
while i <= n:
  i = i+1
  print (i)

1.Print all integers from 1 to n

2.Print all integers from 1 to n-1

3.Print all integers from 2 to n

4.Print all integers from 2 to n+1  

ANSWER :- (4) it will dispay all integers from 2 to n+1 as i=1 & i=i+1 is increasing its value by 1.

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Q.2. What will the output of the following Python3 program (using python 3.X version)? n = 13

sum = 0
while (n > 1):
  n = n//2
  sum = sum + n
print(sum)

1.13

2.10

3.6

4.9

ANSWER :- (2) Here output is 10 as sum=sum+n is summing up all the numbers which appear in n and print 10 as resultant.

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Q.3. What will the output of the following Python3 program? If the program has error, select the option ERROR (using python 3.X version): n,p = 9,1
while (n >= 1):   
  n,p = n//2,n*p
  print(int(p))

1.       8

2.      102

3.      9    
                36
                72
                72

4.     Error

ANSWER :- (3) Here it will return 9,36,72,72 as output when executed on a python idle.

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Q.4. The following code should print all positive even numbers less than or equal to N. N is taken as input from the user. What should replace the X for the code to work correctly?(using python 3.X version): N = int(input('Enter N:'))

i = 1
while ( i < N ) :
    if ( X ):
        print(i)
    i = i + 1

1.i//2 == 0

2.i%2 != 0

3.i//2 != 0

4.i%2 == 0

ANSWER :- (4) Here when i%2==0 condition is taken in place of x it will return all positive even number less than n.

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Q.5. The following code should print all positive odd numbers less than or equal to N. N is taken as input from the user. What should replace the X for the code to work correctly? (using python 3.X version): N = int(input('Enter N:'))
i = 1
while ( i < N ) :   
    print(i)
    X

1.i%2 == 1

2.i = i + 2

3.i = 1 + i * 2

4.i = i * 2

ANSWER :- (2) When we replace i=i+2 at place of x then after result is the positive odd number less than n as i=1 which is odd & i=i+2 will take the number to another odd number.

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